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2y^2-39y+54=0
a = 2; b = -39; c = +54;
Δ = b2-4ac
Δ = -392-4·2·54
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-33}{2*2}=\frac{6}{4} =1+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+33}{2*2}=\frac{72}{4} =18 $
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